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| -- 1.学生表 -- student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 -- 2.课程表 -- course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 -- 3.教师表 -- teacher(t_id,t_name) –教师编号,教师姓名 -- 4.成绩表 -- score(s_id,c_id,s_score) –学生编号,课程编号,分数
-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数 SELECT st.*, sc1.s_score, sc2.s_score, co.c_name FROM student AS st INNER JOIN score AS sc1 ON st.s_id = sc1.s_id AND sc1.c_id = '01' INNER JOIN score AS sc2 ON st.s_id = sc2.s_id AND sc2.c_id = '02' INNER JOIN course AS co ON sc1.c_id = co.c_id WHERE sc1.s_score > sc2.s_score;
-- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数 SELECT st.*, sc1.s_score, sc2.s_score, co.c_name FROM student AS st INNER JOIN score AS sc1 ON st.s_id = sc1.s_id AND sc1.c_id = '01' INNER JOIN score AS sc2 ON st.s_id = sc2.s_id AND sc2.c_id = '02' INNER JOIN course AS co ON sc1.c_id = co.c_id WHERE sc1.s_score < sc2.s_score;
-- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩 SELECT st.s_id, st.s_name, AVG(sc.s_score) avgScore FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id GROUP BY st.s_id HAVING avgScore >= 60;
-- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩 -- (包括有成绩的和无成绩的) SELECT st.s_id, st.s_name, AVG(sc.s_score) avgScore FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id GROUP BY st.s_id HAVING avgScore < 60 OR avgScore IS NULL;
-- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩 SELECT st.s_id, st.s_name, COUNT(co.c_id) AS count, SUM(sc.s_score) AS sum FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id LEFT JOIN course AS co ON co.c_id = sc.c_id GROUP BY st.s_id;
-- 6、查询"李"姓老师的数量 SELECT COUNT(t.t_id) FROM teacher AS t WHERE t.t_name LIKE '李%';
-- 7、查询学过"张三"老师授课的同学的信息 SELECT st.*, te.t_name FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id LEFT JOIN course AS co ON co.c_id = sc.c_id LEFT JOIN teacher AS te ON te.t_id = co.t_id WHERE te.t_name = '张三';
-- 8、查询没学过"张三"老师授课的同学的信息 SELECT st.*, te.t_name FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id LEFT JOIN course AS co ON co.c_id = sc.c_id LEFT JOIN teacher AS te ON te.t_id = co.t_id WHERE te.t_name != '张三';
-- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息 SELECT st.*, sc.c_id FROM student AS st LEFT JOIN score AS sc ON sc.s_id = st.s_id WHERE sc.c_id IN ('01', '02');
-- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息 SELECT st.s_id, st.s_name, st.s_sex, st.s_birth, sc1.c_id FROM student AS st LEFT JOIN (SELECT * FROM score WHERE c_id = '01') AS sc1 ON sc1.s_id = st.s_id LEFT JOIN (SELECT * FROM score WHERE c_id = '02') AS sc2 ON sc2.s_id = st.s_id WHERE sc1.c_id = '01' AND sc2.c_id IS NULL;
-- 11、查询没有学全所有课程的同学的信息 SELECT st.*, COUNT(c_id) AS num FROM student AS st #分组统计每个学生的课程数,不等于总可成熟 LEFT JOIN score sc ON st.s_id = sc.s_id GROUP BY sc.s_id HAVING num != (SELECT COUNT(c_id) FROM course); #查询课程的总数
-- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 SELECT st.*, tmp.c_id FROM student AS st, ( #查询分数表中在01课程id内的学生id SELECT DISTINCT sc.s_id, sc.c_id FROM score AS sc WHERE c_id IN ( #学生01学过的课程id SELECT c_id FROM score WHERE s_id = '01' ) ) AS tmp WHERE st.s_id = tmp.s_id;
-- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 SELECT st.* FROM student AS st WHERE st.s_id IN ( #查询分数表里与01一样的分数个数的学生id(排除01) SELECT s_id FROM score WHERE s_id != '01' AND c_id IN ( #查询01同学的课程id SELECT c_id FROM score WHERE s_id = '01' ) GROUP BY s_id HAVING COUNT(*) = ( #查询01同学学过课程个数 SELECT COUNT(*) FROM score WHERE s_id = '01' ) );
-- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名 SELECT st.* FROM student AS st WHERE st.s_id NOT IN ( #查询学过张三老师对应课程的学生id SELECT sc.s_id FROM score AS sc WHERE sc.c_id IN ( #查询张三老师教的课程id SELECT co.c_id FROM course AS co, teacher AS te WHERE co.t_id = te.t_id AND te.t_name = '张三' ) );
-- 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 SELECT st.s_id, st.s_name, count(*) failCount, avg(sc.s_score) avg FROM score sc LEFT JOIN student st ON sc.s_id = st.s_id WHERE sc.s_score < 60 #先查不及格的数量>2的学生id GROUP BY sc.s_id HAVING failCount >= 2;
-- 16、检索"01"课程分数小于60,按分数降序排列的学生信息 SELECT st.*, sc.s_score FROM score sc LEFT JOIN student st ON sc.s_id = st.s_id WHERE sc.c_id = '01' AND sc.s_score < 60 ORDER BY sc.s_score DESC;
-- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩 SELECT st.*, sc.s_score, t.avg FROM student st LEFT JOIN score sc ON sc.s_id = st.s_id LEFT JOIN (SELECT s_id, avg(s_score) avg FROM score GROUP BY s_id) t ON t.s_id = st.s_id ORDER BY avg DESC;
-- 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率 -- 及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90 SELECT c.c_id, c.c_name, MAX(sc.s_score) "最高分", MIN(sc.s_score) "最低分", AVG(sc.s_score) "平均分" ,((SELECT COUNT(s_id) FROM score WHERE s_score>=60 AND c_id=c.c_id )/(SELECT COUNT(s_id) FROM score WHERE c_id=c.c_id)) "及格率" ,((SELECT COUNT(s_id) FROM score WHERE s_score>=70 AND s_score<80 AND c_id=c.c_id )/(SELECT COUNT(s_id) FROM score WHERE c_id=c.c_id)) "中等率" ,((SELECT COUNT(s_id) FROM score WHERE s_score>=80 AND s_score<90 AND c_id=c.c_id )/(SELECT COUNT(s_id) FROM score WHERE c_id=c.c_id)) "优良率" ,((SELECT COUNT(s_id) FROM score WHERE s_score>=90 AND c_id=c.c_id )/(SELECT COUNT(s_id) FROM score WHERE c_id=c.c_id)) "优秀率" FROM course c LEFT JOIN score sc ON sc.c_id=c.c_id GROUP BY c.c_id;
-- 19、按各科成绩进行排序,并显示排名 SET @rank = 0; SELECT sc.*, @rank := @rank + 1 AS r FROM score sc ORDER BY sc.s_score;
-- 20、查询学生的总成绩并进行排名 SET @rank = 0; SELECT a.*, @rank := @rank + 1 AS r FROM (SELECT sc.*, sum(sc.s_score) scoreSum FROM score sc GROUP BY s_id ORDER BY scoreSum DESC) AS a;
-- 21、查询不同老师所教不同课程平均分从高到低显示 SELECT t.t_id AS 老师ID, t.t_name AS 老师姓名, c.c_id AS 课程ID, c.c_name AS 课程名称, ROUND(AVG(s.s_score), 2) AS 课程平均分 FROM Teacher t JOIN Course c ON t.t_id = c.t_id JOIN Score s ON c.c_id = s.c_id GROUP BY t.t_id, t.t_name, c.c_id, c.c_name ORDER BY 课程平均分 DESC;
-- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩 -- 先为每门课程的成绩排名,再筛选2-3名 SELECT st.s_id AS 学生ID, st.s_name AS 学生姓名, st.s_sex AS 学生性别, c.c_name AS 课程名称, sr.s_score AS 成绩, sr.rk AS 排名 FROM ( SELECT sc.s_id, sc.c_id, sc.s_score, -- 用变量实现按课程分区排名(核心逻辑) @rk := IF(@pre_cid = sc.c_id, @rk + 1, 1) AS rk, @pre_cid := sc.c_id -- 记录上一个课程ID,用于分区 FROM Score sc, -- 初始化变量(必须放在这里) (SELECT @pre_cid := '', @rk := 0) AS temp -- 先按课程ID分组,再按成绩降序排序(排名的关键前提) ORDER BY sc.c_id, sc.s_score DESC ) AS sr -- 关联学生表和课程表获取完整信息 JOIN Student st ON sr.s_id = st.s_id JOIN Course c ON sr.c_id = c.c_id -- 筛选第2、3名 WHERE sr.rk IN (2, 3) -- 最终排序:按课程、按排名 ORDER BY c.c_id, sr.rk;
-- 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比 SELECT c.c_id AS 课程编号, c.c_name AS 课程名称, -- 各分数段人数 SUM(CASE WHEN s.s_score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS `100-85`, SUM(CASE WHEN s.s_score BETWEEN 70 AND 84 THEN 1 ELSE 0 END) AS `85-70`, SUM(CASE WHEN s.s_score BETWEEN 60 AND 69 THEN 1 ELSE 0 END) AS `70-60`, SUM(CASE WHEN s.s_score BETWEEN 0 AND 59 THEN 1 ELSE 0 END) AS `0-60`, -- 各分数段百分比(保留2位小数) ROUND(SUM(CASE WHEN s.s_score BETWEEN 85 AND 100 THEN 1 ELSE 0 END)/COUNT(s.s_score)*100,2) AS `100-85占比(%)`, ROUND(SUM(CASE WHEN s.s_score BETWEEN 70 AND 84 THEN 1 ELSE 0 END)/COUNT(s.s_score)*100,2) AS `85-70占比(%)`, ROUND(SUM(CASE WHEN s.s_score BETWEEN 60 AND 69 THEN 1 ELSE 0 END)/COUNT(s.s_score)*100,2) AS `70-60占比(%)`, ROUND(SUM(CASE WHEN s.s_score BETWEEN 0 AND 59 THEN 1 ELSE 0 END)/COUNT(s.s_score)*100,2) AS `0-60占比(%)` FROM Course c JOIN Score s ON c.c_id = s.c_id GROUP BY c.c_id, c.c_name;
-- 24、查询学生平均成绩及其名次 SELECT sa.s_id AS 学生ID, sa.s_name AS 学生姓名, sa.平均成绩, @rank := @rank + 1 AS 名次 FROM ( SELECT s.s_id, s.s_name, ROUND(AVG(sc.s_score), 2) AS 平均成绩 FROM Student s JOIN Score sc ON s.s_id = sc.s_id GROUP BY s.s_id, s.s_name ORDER BY 平均成绩 DESC ) AS sa, (SELECT @rank := 0) AS temp;
-- 25、查询各科成绩前三名的记录 SELECT st.s_id AS 学生ID, st.s_name AS 学生姓名, c.c_name AS 课程名称, sr.s_score AS 成绩, sr.rk AS 排名 FROM ( SELECT sc.s_id, sc.c_id, sc.s_score, @rk := IF(@pre_cid = sc.c_id, @rk + 1, 1) AS rk, @pre_cid := sc.c_id FROM Score sc, (SELECT @pre_cid := '', @rk := 0) AS temp ORDER BY sc.c_id, sc.s_score DESC ) AS sr JOIN Student st ON sr.s_id = st.s_id JOIN Course c ON sr.c_id = c.c_id WHERE sr.rk <= 3 ORDER BY c.c_id, sr.rk;
-- 26、查询每门课程被选修的学生数 SELECT c.c_id AS 课程编号, c.c_name AS 课程名称, COUNT(DISTINCT sc.s_id) AS 选修学生数 FROM Course c LEFT JOIN Score sc ON c.c_id = sc.c_id GROUP BY c.c_id, c.c_name;
-- 27、查询出只有两门课程的全部学生的学号和姓名 SELECT s.s_id AS 学生ID, s.s_name AS 学生姓名 FROM Student s JOIN Score sc ON s.s_id = sc.s_id GROUP BY s.s_id, s.s_name HAVING COUNT(DISTINCT sc.c_id) = 2;
-- 28、查询男生、女生人数 SELECT s_sex AS 性别, COUNT(*) AS 人数 FROM Student GROUP BY s_sex;
-- 29、查询名字中含有"风"字的学生信息 SELECT * FROM Student WHERE s_name LIKE '%风%';
-- 30、查询同名同性学生名单,并统计同名人数, SELECT IFNULL(s.s_id, '无') AS 学生ID, IFNULL(s.s_name, '无同名同性学生') AS 学生姓名, IFNULL(s.s_sex, '') AS 性别, IFNULL(nsc.同名人数, 0) AS 同名人数 FROM ( SELECT s_name, s_sex, COUNT(*) AS 同名人数 FROM Student GROUP BY s_name, s_sex HAVING COUNT(*) > 1 ) AS nsc LEFT JOIN Student s ON s.s_name = nsc.s_name AND s.s_sex = nsc.s_sex UNION ALL -- 无重复时补充一行提示 SELECT '无', '无同名同性学生', '', 0 FROM DUAL WHERE NOT EXISTS ( SELECT 1 FROM Student GROUP BY s_name, s_sex HAVING COUNT(*) > 1 );
-- 31、查询1990年出生的学生名单 SELECT * FROM Student WHERE s_birth LIKE '1990-%';
-- 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 SELECT c.c_id AS 课程编号, c.c_name AS 课程名称, ROUND(AVG(sc.s_score), 2) AS 平均成绩 FROM Course c JOIN Score sc ON c.c_id = sc.c_id GROUP BY c.c_id, c.c_name ORDER BY 平均成绩 DESC, c.c_id ASC;
-- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 SELECT s.s_id AS 学生ID, s.s_name AS 学生姓名, ROUND(AVG(sc.s_score), 2) AS 平均成绩 FROM Student s JOIN Score sc ON s.s_id = sc.s_id GROUP BY s.s_id, s.s_name HAVING AVG(sc.s_score) >= 85;
-- 34、查询课程名称为"数学",且分数低于60的学生姓名和分数 SELECT s.s_name AS 学生姓名, sc.s_score AS 分数 FROM Student s JOIN Score sc ON s.s_id = sc.s_id JOIN Course c ON sc.c_id = c.c_id WHERE c.c_name = '数学' AND sc.s_score < 60;
-- 35、查询所有学生的课程及分数情况; SELECT s.s_id AS 学生ID, s.s_name AS 学生姓名, c.c_name AS 课程名称, IFNULL(sc.s_score, '无成绩') AS 分数 FROM Student s CROSS JOIN Course c LEFT JOIN Score sc ON s.s_id = sc.s_id AND c.c_id = sc.c_id ORDER BY s.s_id, c.c_id;
-- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数 SELECT s.s_name AS 学生姓名, c.c_name AS 课程名称, sc.s_score AS 分数 FROM Student s JOIN Score sc ON s.s_id = sc.s_id JOIN Course c ON sc.c_id = c.c_id WHERE sc.s_score > 70 ORDER BY s.s_name, c.c_name;
-- 37、查询不及格的课程 SELECT s.s_id AS 学生ID, s.s_name AS 学生姓名, c.c_name AS 课程名称, sc.s_score AS 分数 FROM Student s JOIN Score sc ON s.s_id = sc.s_id JOIN Course c ON sc.c_id = c.c_id WHERE sc.s_score < 60 ORDER BY c.c_name, sc.s_score;
-- 38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名 SELECT s.s_id AS 学生ID, s.s_name AS 学生姓名 FROM Student s JOIN Score sc ON s.s_id = sc.s_id WHERE sc.c_id = '01' AND sc.s_score >= 80;
-- 39、求每门课程的学生人数 SELECT c.c_id AS 课程编号, c.c_name AS 课程名称, COUNT(DISTINCT sc.s_id) AS 学生人数 FROM Course c LEFT JOIN Score sc ON c.c_id = sc.c_id GROUP BY c.c_id, c.c_name;
-- 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩 SELECT st.s_id AS 学生ID, st.s_name AS 学生姓名, st.s_birth AS 生日, st.s_sex AS 性别, c.c_name AS 课程名称, sr.s_score AS 最高成绩 FROM ( SELECT sc.s_id, sc.c_id, sc.s_score, @rk := IF(@pre_cid = sc.c_id, @rk + 1, 1) AS rk, @pre_cid := sc.c_id FROM ( -- 先筛选张三老师的课程成绩并排序(独立子查询避免优化器干扰) SELECT sc.s_id, sc.c_id, sc.s_score FROM Score sc JOIN Course c ON sc.c_id = c.c_id JOIN Teacher t ON c.t_id = t.t_id WHERE t.t_name = '张三' ORDER BY sc.c_id, sc.s_score DESC ) AS sc, (SELECT @pre_cid := '', @rk := 0) AS temp ) AS sr JOIN Student st ON sr.s_id = st.s_id JOIN Course c ON sr.c_id = c.c_id WHERE sr.rk = 1;
-- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 SELECT sc1.s_id AS 学生ID, sc1.c_id AS 课程1编号, sc2.c_id AS 课程2编号, sc1.s_score AS 成绩 FROM Score sc1 JOIN Score sc2 ON sc1.s_id = sc2.s_id AND sc1.c_id <> sc2.c_id AND sc1.s_score = sc2.s_score ORDER BY sc1.s_id, sc1.s_score;
-- 42、查询每门功成绩最好的前两名 SELECT st.s_id AS 学生ID, st.s_name AS 学生姓名, c.c_name AS 课程名称, sr.s_score AS 成绩, sr.rk AS 排名 FROM ( SELECT sc.s_id, sc.c_id, sc.s_score, @rk := IF(@pre_cid = sc.c_id, @rk + 1, 1) AS rk, @pre_cid := sc.c_id FROM Score sc, (SELECT @pre_cid := '', @rk := 0) AS temp ORDER BY sc.c_id, sc.s_score DESC ) AS sr JOIN Student st ON sr.s_id = st.s_id JOIN Course c ON sr.c_id = c.c_id WHERE sr.rk <= 2 ORDER BY c.c_id, sr.rk;
-- 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列 SELECT c.c_id AS 课程编号, COUNT(DISTINCT sc.s_id) AS 选修人数 FROM Course c JOIN Score sc ON c.c_id = sc.c_id GROUP BY c.c_id HAVING COUNT(DISTINCT sc.s_id) > 5 ORDER BY 选修人数 DESC, c.c_id ASC;
-- 44、检索至少选修两门课程的学生学号 SELECT s_id AS 学生ID FROM Score GROUP BY s_id HAVING COUNT(DISTINCT c_id) >= 2;
-- 45、查询选修了全部课程的学生信息 SELECT s.* FROM Student s JOIN Score sc ON s.s_id = sc.s_id GROUP BY s.s_id, s.s_name, s.s_birth, s.s_sex HAVING COUNT(DISTINCT sc.c_id) = (SELECT COUNT(*) FROM Course);
-- 46、查询各学生的年龄 SELECT s_id AS 学生ID, s_name AS 学生姓名, YEAR(NOW()) - YEAR(STR_TO_DATE(s_birth, '%Y-%m-%d')) AS 年龄 FROM Student;
-- 47、查询本周过生日的学生 -- 真实时间 SELECT * FROM Student WHERE -- 提取生日的月-日,转换为当年日期 STR_TO_DATE(CONCAT(YEAR(NOW()), '-', DATE_FORMAT(STR_TO_DATE(s_birth, '%Y-%m-%d'), '%m-%d')), '%Y-%m-%d') -- 判断是否在本周(周一到周日) BETWEEN DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY) AND DATE_ADD(CURDATE(), INTERVAL 6 - WEEKDAY(CURDATE()) DAY); -- 限定时间 SELECT * FROM Student WHERE STR_TO_DATE(CONCAT('1990', '-', DATE_FORMAT(STR_TO_DATE(s_birth, '%Y-%m-%d'), '%m-%d')), '%Y-%m-%d') BETWEEN '1990-01-01' AND '1990-01-07';
-- 48、查询下周过生日的学生 SELECT * FROM Student WHERE DATE_FORMAT(STR_TO_DATE(s_birth, '%Y-%m-%d'), '%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) - 7 DAY), '%m-%d') AND DATE_FORMAT(DATE_ADD(CURDATE(), INTERVAL 6 - WEEKDAY(CURDATE()) + 7 DAY), '%m-%d');
-- 49、查询本月过生日的学生 -- 方式1:基础版(按系统当前月份查询) SELECT * FROM Student WHERE MONTH(STR_TO_DATE(s_birth, '%Y-%m-%d')) = MONTH(NOW());
-- 方式2:固定测试版(强制查询1月过生日的学生,直接验证结果) -- (手动指定月份为1,可查到赵雷、王菊等1月生日的学生) SELECT * FROM Student WHERE MONTH(STR_TO_DATE(s_birth, '%Y-%m-%d')) = 1;
-- 50、查询下月过生日的学生 -- 注意:当 当前月为12时,用month(now())+1为13而不是1,可用timestampadd()函数或mod取模 SELECT * FROM Student WHERE MONTH(STR_TO_DATE(s_birth, '%Y-%m-%d')) = MONTH(DATE_ADD(NOW(), INTERVAL 1 MONTH));
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