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| # 利用to_days函数查询今天的数据: select * from 表名 where to_days(时间字段名) = to_days(now()); to_days函数:返回从0000年(公元1年)至当前日期的总天数。 # 昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) <= 1 # 7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名) # 近30天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名) # 本月 SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m' ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m' ) # 上一月 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m' ) , date_format( 时间字段名, ‘%Y%m' ) ) =1 # 本季度 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); # 上季度 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); # 本年 select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW()); # 上年 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year)); # 当前这周 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now()); # 上周 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1; # 当前月份 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m') # 距离当前现在6个月 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); # 上个月 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from ` user ` where DATE_FORMAT(pudate, ‘ %Y%m ‘ ) = DATE_FORMAT(CURDATE(), ‘ %Y%m ‘ ) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now()) select * from [ user ] where YEAR (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR (now()) and MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now()) select * from [ user ] where pudate between 上月最后一天 and 下月第一天 where date(regdate) = curdate(); select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now()) SELECT date( c_instime ) ,curdate( ) FROM `t_score` WHERE 1 LIMIT 0 , 30
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